7[1+p]-1=3p-2+4[p+2]

Solution for 7[1+p]-1=3p-2+4[p+2] equation:

Simplifying
7[1 + p] + -1 = 3p + -2 + 4[p + 2]
[1 * 7 + p * 7] + -1 = 3p + -2 + 4[p + 2]
[7 + 7p] + -1 = 3p + -2 + 4[p + 2]

Reorder the terms:
7 + -1 + 7p = 3p + -2 + 4[p + 2]

Combine like terms: 7 + -1 = 6
6 + 7p = 3p + -2 + 4[p + 2]

Reorder the terms:
6 + 7p = 3p + -2 + 4[2 + p]
6 + 7p = 3p + -2 + [2 * 4 + p * 4]
6 + 7p = 3p + -2 + [8 + 4p]

Reorder the terms:
6 + 7p = -2 + 8 + 3p + 4p

Combine like terms: -2 + 8 = 6
6 + 7p = 6 + 3p + 4p

Combine like terms: 3p + 4p = 7p
6 + 7p = 6 + 7p

Add '-6' to each side of the equation.
6 + -6 + 7p = 6 + -6 + 7p

Combine like terms: 6 + -6 = 0
0 + 7p = 6 + -6 + 7p
7p = 6 + -6 + 7p

Combine like terms: 6 + -6 = 0
7p = 0 + 7p
7p = 7p

Add '-7p' to each side of the equation.
7p + -7p = 7p + -7p

Combine like terms: 7p + -7p = 0
0 = 7p + -7p

Combine like terms: 7p + -7p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.